0=x^2+30x-445

Solution for 0=x^2+30x-445 equation:

0=x^2+30x-445

We move all terms to the left:

0-(x^2+30x-445)=0

We add all the numbers together, and all the variables

-(x^2+30x-445)=0

We get rid of parentheses

-x^2-30x+445=0

We add all the numbers together, and all the variables

-1x^2-30x+445=0

a = -1; b = -30; c = +445;
Δ = b2-4ac
Δ = -302-4·(-1)·445
Δ = 2680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2680}=\sqrt{4*670}=\sqrt{4}*\sqrt{670}=2\sqrt{670}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{670}}{2*-1}=\frac{30-2\sqrt{670}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{670}}{2*-1}=\frac{30+2\sqrt{670}}{-2}
$